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Find the last node in LinkedList containing the specified value in C#
To find the last node in LinkedList containing the specified value, the code is as follows −
Example
using System;
using System.Collections.Generic;
public class Demo {
public static void Main() {
LinkedList<int> list = new LinkedList<int>();
list.AddLast(100);
list.AddLast(200);
list.AddLast(300);
list.AddLast(400);
list.AddLast(500);
list.AddLast(300);
list.AddLast(500);
Console.WriteLine("LinkedList elements...");
foreach(int i in list) {
Console.WriteLine(i);
}
LinkedListNode<int> val = list.FindLast(300);
Console.WriteLine("Specified value = "+val.Value);
}
}Output
This will produce the following output −
LinkedList elements... 100 200 300 400 500 300 500 Specified value = 300
Example
Let us see another example −
using System;
using System.Collections.Generic;
public class Demo {
public static void Main() {
LinkedList<String> list = new LinkedList<String>();
list.AddLast("One");
list.AddLast("Two");
list.AddLast("Three");
list.AddLast("Four");
list.AddLast("Five");
Console.WriteLine("Elements in LinkedList...");
foreach (string res in list) {
Console.WriteLine(res);
}
LinkedListNode<string> val = list.FindLast("Five");
Console.WriteLine("Specified value = "+val.Value);
}
}Output
This will produce the following output −
Elements in LinkedList... One Two Three Four Five Specified value = Five
Updated on: 11-Dec-2019
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