Suppose we have an array num and another value val, we have to remove all instances of that value in-place and find the new length.
So, if the input is like [0,1,5,5,3,0,4,5] 5, then the output will be 5.
To solve this, we will follow these steps −
count := 0
for each index i of nums
if nums[i] is not equal to val, then −
nums[count] := nums[i]
count := count + 1
Let us see the following implementation to get a better understanding −
class Solution: def removeElement(self, nums, val): count = 0 for i in range(len(nums)): if nums[i] != val : nums[count] = nums[i] count +=1 return count ob = Solution() print(ob.removeElement([0,1,5,5,3,0,4,5], 5))