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Reinterpret 64-bit signed integer to a double-precision floating point number in C#
To reinterpret the specified 64-bit signed integer to a double-precision floating point number, the code is as follows −
Example
using System;
public class Demo {
public static void Main() {
long d = 9846587687;
Console.Write("Value (64-bit signed integer) = "+d);
double res = BitConverter.Int64BitsToDouble(d);
Console.Write("
Value (double-precision floating point number) = "+res);
}
}Output
This will produce the following output −
Value (64-bit signed integer) = 9846587687 Value (double-precision floating point number) = 4.86486070491012E-314
Example
Let us see another example −
using System;
public class Demo {
public static void Main() {
long d = 20;
Console.Write("Value (64-bit signed integer) = "+d);
double res = BitConverter.Int64BitsToDouble(d);
Console.Write("
Value (double-precision floating point number) = "+res);
}
}Output
This will produce the following output −
Value (64-bit signed integer) = 20 Value (double-precision floating point number) = 9.88131291682493E-323
Updated on: 11-Dec-2019
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