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Python – Test if tuple list has a single element
When it is required to test if a tuple list contains a single element, a flag value and a simple iteration is used.
Example
Below is a demonstration of the same
my_list = [(72, 72, 72), (72, 72), (72, 72)]
print("The list is :")
print(my_list)
my_result = True
for sub in my_list:
flag = True
for element in sub:
if element != my_list[0][0]:
flag = False
break
if not flag:
my_result = False
break
if(flag == True):
print("The tuple contains a single element")
else:
print("The tuple doesn't contain a single element")Output
The list is : [(72, 72, 72), (72, 72), (72, 72)] The tuple contains a single element
Explanation
A list of list is defined and is displayed on the console.
A variable is assigned to ‘True’.
The list is iterated over, and a value is flagged as ‘True’.
If an element of the list is not equal to the first element of the list, the value is flagged to ‘False’.
Otherwise, the variable is changed to ‘False.
The control is broken outpf the loop.
Outside the method, if the flagged value is ‘True’, it means the list contains a single element only.
Relevant message is displayed on the console.
Updated on: 14-Sep-2021
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