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Python – Test if all rows contain any common element with other Matrix
When it is required to test if all rows contain any common element with other matrix, a simple iteration and a flag value are used.
Example
Below is a demonstration of the same
my_list_1 = [[3, 16, 1], [2, 4], [4, 31, 31]]
my_list_2 = [[42, 16, 12], [42, 8, 12], [31, 7, 10]]
print("The first list is :")
print(my_list_1)
print("The second list is :")
print(my_list_2)
my_result = True
for idx in range(0, len(my_list_1)):
temp = False
for element in my_list_1[idx]:
if element in my_list_2[idx]:
temp = True
break
if not temp :
my_result = False
break
if(temp == True):
print("The two matrices contain common elements")
else:
print("The two matrices don't contain common elements")Output
The first list is : [[3, 16, 1], [2, 4], [4, 31, 31]] The second list is : [[42, 16, 12], [42, 8, 12], [31, 7, 10]] The two matrices don't contain common elements
Explanation
Two lists of lists are defined and are displayed on the console.
A variable is set to Boolean ‘True’.
The first list is iterated and a temporary variable is set to Boolean ‘False’.
If the element is present in the second list, then the temporary variable is set to Boolean ‘True’.
The control breaks out of the loop.
If the temporary variable is False outside the loop, the control breaks out of the loop.
In the end, based on the value of the temporary variable, the relevant message is displayed on the console.
Updated on: 14-Sep-2021
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