# Python program to show diamond pattern with 2n-1 lines

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Suppose we have a number n. We have to draw a diamond pattern with asterisks with 2n-1 lines. First 1 to n lines contain 1 to n number of asterisks, and next they are decreasing from n-1 to 1.

So, if the input is like n = 5, then the output will be

    *
* *
* * *
* * * *
* * * * *
* * * *
* * *
* *
*

To solve this, we will follow these steps −

• for i in range 1 to n, do

• print a block '* ' i times and print it in justified format in center with (2*n-1) characters space in each line
• for i in range n-1 to 0, decrease by 1, do

• print a block '* ' i times and print it in justified format in center with (2*n-1) characters space in each line

## Example

Let us see the following implementation to get better understanding

def solve(n):
for i in range(1,n+1):
print(('* '*i).center(2*n-1))
for i in range(n-1,0, -1):
print(('* '*i).center(2*n-1))

n = 10
solve(n)

## Input

10


## Output

         *
* *
* * *
* * * *
* * * * *
* * * * * *
* * * * * * *
* * * * * * * *
* * * * * * * * *
* * * * * * * * * *
* * * * * * * * *
* * * * * * * *
* * * * * * *
* * * * * *
* * * * *
* * * *
* * *
* *
*
Updated on 11-Oct-2021 11:07:52

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