Python program to print Rows where all its Elements’ frequency is greater than K

When it is required to print rows where all its elements’ frequency is greater than K, a method is defined that takes two parameters, and uses ‘all’ operator and iteration to give the result.

Below is a demonstration of the same −

Example

def frequency_greater_K(row, K) :
   return all(row.count(element) > K for element in row)
my_list = [[11, 11, 32, 43, 12, 23], [42, 14, 55, 62, 16], [11, 11, 11, 11], [42, 54, 61, 18]]
print("The tuple is :")
print(my_list)
K = 1
print("The value of K is :")
print(K)
my_result = [row for row in my_list if frequency_greater_K(row, K)]
print("The result is :")
print(my_result)

Output

The tuple is :
[[11, 11, 32, 43, 12, 23], [42, 14, 55, 62, 16], [11, 11, 11, 11], [42, 54, 61, 18]]
The value of K is :
1
The result is :
[[11, 11, 11, 11]]

Explanation

• A method named ‘frequency_greater_K’ is defined that takes row and K value as parameters, and returns the comparison between element count and key as output.

• A list of list is defined and displayed on the console.

• A list comprehension is used to iterate over the list, and the method is called on every list.

• This result is assigned to a variable.

• This is the output that is displayed on the console.

AmitDiwan

Updated on 07-Sep-2021 12:56:19

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