Python program to print Possible Words using given characters

PythonServer Side ProgrammingProgramming

In this tutorial, we are going to find all the possible words with the given characters. Let's see some test cases for better understanding.

words = ["hi", "hello", "bye", "good"]
characters = ["h", "i", "b", "y", "e"]

Let's follow the below steps to achieve our goal.


1. Initialize the words and characters list.
2. Write a function which returns a dictionary containing a count of each char of the word.
   2.1. Initialise an empty dictionary.
   2.2. Iterate through the word, and increment char count by one if already present else initialise it with one.
   2.3. After the loop return dictionary.
3. Iterate through the words list.
   3.1. Initialise a variable flag with 1.
   3.2. Find char count with the help of above function and store it in a variable.
   3.3. Iterate through the above-returned dictionary.
      3.3.1. Check whether the key is in the characters or not. If not present, make the flag to zero.
      3.3.2 Else check for the equality count of character in characters and dictionary. If not equal, make a flag to zero.
3.4. If the flag is equal to one.
   3.4.1. Print the word.

Let's implement the above algorithm.


## initializing the lists
words = ["hi", "hello", "bye", "good"]
characters = ["h", "i", "b", "y", "e"]
## function which returns dictionary containing char counts
def char_count(word):
   ## initializing an empty dictionary
   char_count = {}
   ## loop to find the frequency of the chars
   for char in word:
      ## incrementing the char count by one
      char_count[char] = char_count.get(char, 0) + 1
   ## returning dictionary
   return char_count
## iterating through the words list
for word in words:
   ## initializing flag to one
   flag = 1
   ## getting the char count using char_count() function
   chars = char_count(word)
   ## iterating through the chars
   for key in chars:
      ## checking for the presence of key in the characters
      if key not in characters:
         ## updating the flag value to zero
         flag = 0
         ## comparing the count of chars in chars and characters
         if characters.count(key) != chars[key]:
            ## updating the flag value to zero
            flag = 0
      ## checking the flag value
      if flag == 1:


If you run the above program, you will get the following results.



If you have any doubts regarding the tutorial, mention them in the comment section.

Published on 23-Oct-2019 10:28:42