Python program to convert float decimal to octal number

Octal Number uses eight digits, 0,1,2,3,4,5,6,7. Also called as base 8 number system. Each position in an octal number represents a 0 power of the base (8). Last position in an octal number represents a x power of the base (8).

Decimal number system has base 10 as it uses 10 digits from 0 to 9. In decimal number system, the successive positions to the left of the decimal point represent units, tens, hundreds, thousands, and so on.

Given a float decimal value and input the decimal places number, our task is to convert it to octal form. Let’s say we have the following floating-point number −

6.89

At first, we take the integer part from the floating-point value and convert it to octal then we take fractional part and convert it to octal form and lastly combine both. Consider decimal places 12. The output will be −

6.707534121727

Convert floating to octal by taking user input

Example

def float_convert_octal(my_number, places = 3):
	my_whole, my_dec = str(my_number).split(".")
	my_whole = int(my_whole)
	my_dec = int (my_dec)
	res = oct(my_whole).lstrip("0o") + "."
	for x in range(places):
		my_whole, my_dec = str((decimal_converter(my_dec)) * 8).split(".")
		my_dec = int(my_dec)
		res += my_whole
	return res
def decimal_converter(num):
	while num > 1:
		num /= 10
	return num
n = input("Enter the floating point value : \n")
p = int(input("Enter the number of decimal places of the result : \n"))
print(float_convert_octal(n, places = p))

Output

Enter the floating point value :
6.89
Enter the number of decimal places of the result :
12
6.707534121727