Python program to calculate Date, Month and Year from Seconds

When working with timestamps, you often need to convert seconds (Unix epoch time) into readable date components. Python provides several approaches using the datetime module, time module, or manual calculations with divmod().

Using datetime Module

The datetime module offers classes to manipulate dates and times. The utcfromtimestamp() function converts seconds since epoch (January 1, 1970) into a datetime object.

Syntax

datetime.datetime.utcfromtimestamp(seconds)

Example

Here we convert 1706472809 seconds to extract the day, month, and year components ?

import datetime

def calculate_date(seconds):
    date = datetime.datetime.utcfromtimestamp(seconds)
    year = date.year
    month = date.month
    day = date.day
    return day, month, year

seconds = 1706472809
day, month, year = calculate_date(seconds)
print("Day:", day, "Month:", month, "Year:", year)

Day: 28 Month: 1 Year: 2024

Using time Module

The time module provides the gmtime() function which converts seconds to a time tuple containing various time components including year, month, and day.

Syntax

time.gmtime(seconds)

Example

The gmtime() function returns a struct_time object with accessible attributes ?

import time

def calculate_date(seconds):
    time_tuple = time.gmtime(seconds)
    day = time_tuple.tm_mday
    month = time_tuple.tm_mon
    year = time_tuple.tm_year
    return day, month, year

seconds = 1706472809 
day, month, year = calculate_date(seconds)
print("Day:", day, "Month:", month, "Year:", year)

Day: 28 Month: 1 Year: 2024

Using divmod() Function

The divmod() function performs division and returns both quotient and remainder. This approach manually calculates the date by converting seconds to days and handling leap years.

Syntax

quotient, remainder = divmod(dividend, divisor)

Example

This method manually converts seconds to years, months, and days by accounting for leap years ?

def calculate_date(seconds):
    minutes, seconds = divmod(seconds, 60)
    hours, minutes = divmod(minutes, 60)
    days, hours = divmod(hours, 24)
    
    year = 1970
    while days > 365:
        if year % 4 == 0 and (year % 100 != 0 or year % 400 == 0):
            if days > 366:
                days -= 366
                year += 1
            else:
                break
        else:
            days -= 365
            year += 1
    
    # Days in each month, accounting for leap year
    month_days = [31, 28 + (year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)), 
                  31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
    
    month = 1
    while days >= month_days[month - 1]:
        days -= month_days[month - 1]
        month += 1
    
    return days + 1, month, year

seconds = 1706472809  
day, month, year = calculate_date(seconds)
print("Day:", day, "Month:", month, "Year:", year)

Day: 28 Month: 1 Year: 2024

Comparison

Conclusion

The datetime module's utcfromtimestamp() is the most straightforward approach for converting seconds to date components. Use the manual divmod() method only when you need to understand the underlying calculation process.