# Python Program for Find sum of odd factors of a number

PythonServer Side ProgrammingProgramming

## Problem statement

Given a number input n, the task is to Find the sum of odd factors of a number.

Here we first need to eliminate all the even factors.

To remove all even factors, we repeatedly divide n till it is divisible by 2. After this step, we only get the odd factors of the number.

Below is the implementation −

## Example

Live Demo

import math
def sumofoddFactors( n ):
#prime factors
res = 1
# ignore even factors
while n % 2 == 0:
n = n // 2
for i in range(3, int(math.sqrt(n) + 1)):
count = 0
curr_sum = 1
curr_term = 1
while n % i == 0:
count+=1
n = n // i
curr_term *= i
curr_sum += curr_term
res *= curr_sum
# n is a prime number.
if n >= 2:
res *= (1 + n)
return res
# main
n = 27
print(sumofoddFactors(n))

## Output

41

All the variables are declared in the global frame as shown in the figure given below − ## Conclusion

In this article, we learnt about the approach to Find sum of odd factors of a number