- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Python Pandas - Return the label from the index if all of the labels in the index are later than the passed label
To return the label from the index if all of the labels in the index are later than the passed label, use the index.asof() method in Pandas.
At first, import the required libraries −
import pandas as pd
Creating Pandas index −
index = pd.Index([10, 20, 30, 40, 50, 60, 70])
Display the Pandas index −
print("Pandas Index...\n",index)
Return the label from the index. Returns NaN when if all of the labels in the index are later than the passed label −
print("\nGet the label from the index...\n",index.asof(6))
Example
Following is the code −
import pandas as pd # Creating Pandas index index = pd.Index([10, 20, 30, 40, 50, 60, 70]) # Display the Pandas index print("Pandas Index...\n",index) # Return the number of elements in the Index print("\nNumber of elements in the index...\n",index.size) # Return the label from the index # Returns NaN when if all of the labels in the index are later than the passed label print("\nGet the label from the index...\n",index.asof(6))
Output
This will produce the following output −
Pandas Index... Int64Index([10, 20, 30, 40, 50, 60, 70], dtype='int64') Number of elements in the index... 7 Get the label from the index... Nan
Advertisements