Python Pandas - Return the count of increments applied on the given DateOffset object

PythonServer Side ProgrammingProgramming

To return the count of increments applied on the given DateOffset object, use the offset.n property in Pandas. At first, import the required libraries −

from pandas.tseries.frequencies import to_offset
import pandas as pd

Set the timestamp object in Pandas −

timestamp = pd.Timestamp('2021-09-26 03:25:02.000045')

Create the DateOffset. We are incrementing the months here using the "M" frequency −

offset = to_offset("5M")

Display the Updated Timestamp −

print("\nUpdated Timestamp...\n",timestamp + offset)

Return the count of increments on the given DateOffset object −

print("\nThe count of increments on the DateOffset object..\n", offset.n)

Example

Following is the code −

from pandas.tseries.frequencies import to_offset
import pandas as pd

# Set the timestamp object in Pandas
timestamp = pd.Timestamp('2021-09-26 03:25:02.000045')

# Display the Timestamp
print("Timestamp...\n",timestamp)

# Create the DateOffset
# We are incrementing the months here using the "M" frequency
offset = to_offset("5M")

# Display the DateOffset
print("\nDateOffset...\n",offset)

# Display the Updated Timestamp
print("\nUpdated Timestamp...\n",timestamp + offset)

# return the count of increments on the given DateOffset object
print("\nThe count of increments on the DateOffset object..\n", offset.n)

Output

This will produce the following code −

Timestamp...
 2021-09-26 03:25:02.000045

DateOffset...
 <5 * MonthEnds>

Updated Timestamp...
 2022-01-31 03:25:02.000045

The count of increments on the DateOffset object..
 5
raja
Updated on 21-Oct-2021 07:59:53

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