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Python Pandas - Return the count of increments applied on the CustomBusinessDay offset
To return the count of increments applied on the CustomBusinessDay offset, use the CustomBusinessDay.n property in Pandas.
At first, import the required libraries −
import pandas as pd
Set the timestamp object in Pandas −
timestamp = pd.Timestamp('2021-10-22 03:10:35')
Create the CustomBusinessDay Offset −
cbdOffset = pd.tseries.offsets.CustomBusinessDay(n = 4, weekmask = 'Mon Tue Wed Fri')
Add the offset to the Timestamp and display the Updated Timestamp −
print("\nUpdated Timestamp...\n",timestamp + cbdOffset)
Return the count of increments on the given CustomBusinessDay object −
print("\nThe count of increments on the CustomBusinessDay object..\n", cbdOffset.n)
Example
Following is the code −
import pandas as pd # Set the timestamp object in Pandas timestamp = pd.Timestamp('2021-10-22 03:10:35') # Display the Timestamp print("Timestamp...\n",timestamp) # Create the CustomBusinessDay Offset # CustomBusinessDay is the DateOffset subclass representing custom business days excluding holidays # Weekmask of valid business days cbdOffset = pd.tseries.offsets.CustomBusinessDay(n = 4, weekmask = 'Mon Tue Wed Fri') # Display the CustomBusinessDay Offset print("\nCustomBusinessDay Offset...\n",cbdOffset) # Add the offset to the Timestamp and display the Updated Timestamp print("\nUpdated Timestamp...\n",timestamp + cbdOffset) # Return frequency applied on the given CustomBusinessDay Offset object as a string print("\nFrequency applied on the given CustomBusinessDay Offset object...\n",cbdOffset.freqstr) # return the count of increments on the given CustomBusinessDay object print("\nThe count of increments on the CustomBusinessDay object..\n", cbdOffset.n)
Output
This will produce the following code −
Timestamp... 2021-10-22 03:10:35 CustomBusinessDay Offset... <4 * CustomBusinessDays> Updated Timestamp... 2021-10-29 03:10:35 Frequency applied on the given CustomBusinessDay Offset object... 4C The count of increments on the CustomBusinessDay object.. 4
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