Python Pandas - Form the intersection of two Index objects and sort the result

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To form the intersection of two Index objects, use the index1.intersection(index2) method in Pandas. To sort the result, use the sort parameter.

At first, import the required libraries −

import pandas as pd

Creating Pandas index1 and index2 −

index1 = pd.Index([4, 3, 2, 1])
index2 = pd.Index([8, 2, 6, 4])

Display the Pandas index1 and index2

print("Pandas Index1...\n",index1)
print("Pandas Index2...\n",index2)

Perform intersection. The results are sorted using the "sort" parameter

res = index1.intersection(index2, sort=None)

Example

Following is the code −

import pandas as pd

# Creating Pandas index1 and index2
index1 = pd.Index([4, 3, 2, 1])
index2 = pd.Index([8, 2, 6, 4])

# Display the Pandas index1 and index2
print("Pandas Index1...\n",index1)
print("Pandas Index2...\n",index2)

# Return the number of elements in Index1 and Index2
print("\nNumber of elements in index1...\n",index1.size)
print("\nNumber of elements in index2...\n",index2.size)

# Perform intersection
# The results are sorted using the "sort" parameter
res = index1.intersection(index2, sort=None)

# Intersection of both the indexes and returning sorted result
print("\nThe index1 and index2 intersection (sorted result)...\n",res)

Output

This will produce the following output −

Pandas Index1...
Int64Index([4, 3, 2, 1], dtype='int64')
Pandas Index2...
Int64Index([8, 2, 6, 4], dtype='int64')

Number of elements in index1...
4

Number of elements in index2...
4

The index1 and index2 intersection (sorted result)...
Int64Index([2, 4], dtype='int64')
raja
Published on 14-Oct-2021 06:52:58

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