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Python Pandas - Construct an IntervalArray from an array of splits
To construct an IntervalArray from an array of splits, use the pandas.arrays.IntervalArray.from_breaks().
At first, import the required libraries −
import pandas as pd
Construct a new IntervalArray from an array-like of splits −
array = pd.arrays.IntervalArray.from_breaks([0, 1, 2, 3, 4, 5])
Display the intervals −
print("Our IntervalArray...\n",array)Getting the length of IntervalArray −
print("\nOur IntervalArray length...\n",array.length)
Example
Following is the code −
import pandas as pd
# Construct a new IntervalArray from an array-like of splits
array = pd.arrays.IntervalArray.from_breaks([0, 1, 2, 3, 4, 5])
# Display the IntervalArray
print("Our IntervalArray...\n",array)
# Getting the length of IntervalArray
# Returns an Index with entries denoting the length of each Interval in the IntervalArray
print("\nOur IntervalArray length...\n",array.length)
# midpoint of each Interval in the IntervalArray as an Index
print("\nThe midpoint of each interval in the IntervalArray...\n",array.mid)Output
This will produce the following code −
Our IntervalArray... <IntervalArray> [(0, 1], (1, 2], (2, 3], (3, 4], (4, 5]] Length: 5, dtype: interval[int64, right] Our IntervalArray length... Int64Index([1, 1, 1, 1, 1], dtype='int64') The midpoint of each interval in the IntervalArray... Float64Index([0.5, 1.5, 2.5, 3.5, 4.5], dtype='float64')
Updated on: 13-Oct-2021
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