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Python – Filter consecutive elements Tuples
When it is required to filter consecutive elements from a list of tuple, a method is defined that takes a list of tuple as a parameter and checks the index of every tuple, and returns a Boolean value depending on the index.
Example
Below is a demonstration of the same −
print("Method definition begins...")
def check_consec_tuple_elem(my_tuple):
for idx in range(len(my_tuple) - 1):
if my_tuple[idx + 1] != my_tuple[idx] + 1:
return False
return True
print("Method definition ends...")
my_tuple = [(23, 24, 25, 26), (65, 66, 78, 29), (11, 28, 39), (60, 61, 62, 63)]
print("The list of tuple is : " )
print(my_tuple)
my_result = []
for elem in my_tuple:
if check_consec_tuple_elem(elem):
my_result.append(elem)
print("The resultant tuple is : ")
print(my_result)Output
Method definition begins... Method definition ends... The list of tuple is : [(23, 24, 25, 26), (65, 66, 78, 29), (11, 28, 39), (60, 61, 62, 63)] The resultant tuple is : [(23, 24, 25, 26), (60, 61, 62, 63)]
Explanation
A method named ‘check_consec_tuple_elem’ is defined that takes a tuple as a parameter.
It iterates through the tuple and checks to see if element at an index and the element at the same index incremented by 1 are equal.
If not, it returns False.
Outside the method, a list of tuple is defined and is displayed on the console.
An empty list is defined.
The list of tuple is iterated over, and the method is called by passing every tuple to it.
The result of this is appended to the empty list.
This list is displayed as the output on the console.
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