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Suppose we have a number n in string format. We have to find minimum deci-binary numbers are required, so that whose sum is equal to n. A deci-binary number is a decimal number whose digits are either 0 or 1.

So, if the input is like n = "132", then the output will be 3 because 132 is sum of three decibinary number (10 + 11 + 111).

To solve this, we will follow these steps −

- result := 1
- for each i in n, do
- if i is not in {0,1}, then
- result := maximum of result and i

- if i is not in {0,1}, then
- return result

Let us see the following implementation to get better understanding −

def solve(n): result = 1 for i in n: if i not in {0,1}: result = max(result, int(i)) return result n = "132" print(solve(n))

132

3

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