# Program to find tuple with same product in Python

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Suppose we have an array nums with unique positive values, we have to find the number of tuples (a, b, c, d) such that a*b = c*d where a, b, c, and d are elements of nums, and all elements a, b, c and d are distinct.

So, if the input is like nums = [2,3,4,6], then the output will be 8 because we can get tuples like (2,6,3,4), (2,6,4,3), (6,2,3,4), (6,2,4,3), (3,4,2,6), (4,3,2,6), (3,4,6,2), (4,3,6,2).

To solve this, we will follow these steps −

• dic := an empty map, default value is 0 if some key is not present
• ans:= 0
• for i in range 0 to size of nums - 2, do
• for j in range i+1 to size of nums, do
• dic[nums[i]*nums[j]] := dic[nums[i]*nums[j]] + 1
• for each v in list of all values of dic, do
• if v is same as 1, then
• go for next iteration
• v:= v-1
• s:= (v/2) * (8+8*v)
• ans := ans + s
• return ans as integer

## Example

Let us see the following implementation to get better understanding −

from collections import defaultdict
def solve(nums):
dic = defaultdict(int)
ans=0
for i in range(len(nums)-1):
for j in range(i+1,len(nums)):
dic[nums[i]*nums[j]]+=1
for v in dic.values():
if v==1:
continue
v=v-1
s=(v/2) * (8+8*v)
ans+=s
return int(ans)

nums = [3,4,6,2]
print(solve(nums))

## Input

[3,4,6,2]


## Output

0