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Program to find the winner of an array game using Python
Suppose we have an array called arr, this contains unique elements and we also have another value k. Now consider a game where we take first two elements of the array. In each turn, we compare arr[0] with arr[1], and the larger value wins and remains at position 0 and the smaller value moves to the end of the array. This game will end when a value wins’ k consecutive rounds. We have to find the winner from the array.
So, if the input is like arr = [1,5,6,3,4,2], and k = 3, then the output will be 6 because
round 1, arr = [1,5,6,3,4,2], winner 5, win count for 5 is 1
round 2, arr = [5,6,3,4,2,1], winner 6, win count for 6 is 1
round 3, arr = [6,3,4,2,1,5], winner 6, win count for 6 is 2
round 3, arr = [6,4,2,1,5,3], winner 6, win count for 6 is 3
So winner is 6 as it won three times (k = 3)
To solve this, we will follow these steps −
l := size of arr
prev := arr[0]
count := 0
for i in range 1 to l - 1, do
if prev > arr[i], then
count := count + 1
otherwise,
prev := arr[i]
count := 1
if count is same as k, then
return prev
return prev
Let us see the following implementation to get better understanding −
Example
def solve(arr, k): l = len(arr) prev = arr[0] count = 0 for i in range(1, l): if prev > arr[i]: count+=1 else: prev = arr[i] count = 1 if count == k: return prev return prev arr = [1,5,6,3,4,2] k = 3 print(solve(arr, k))
Input
[1,5,6,3,4,2], 3
Output
6
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