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# Program to find sum of two numbers which are less than the target in Python

Suppose we have a list of numbers called nums and also have a target value, we have to find the sum of the largest pair of numbers in nums whose sum is at most (target-1).

So, if the input is like nums = [8, 3, 4, 9, 2] target = 8, then the output will be 7, because the sum of the largest pair of numbers less than 8 is 4 + 3 = 7.

To solve this, we will follow these steps −

- sort the list nums
- p1 := 0
- p2 := size of nums - 1
- m := -inf
- while p1 < p2, do
- if nums[p1] + nums[p2] < target, then
- m := maximum of m and (nums[p1] + nums[p2])
- p1 := p1 + 1

- otherwise,
- p2 := p2 - 1

- if nums[p1] + nums[p2] < target, then
- return m

## Example

Let us see the following implementation to get better understanding −

import math def solve(nums, target): nums.sort() p1 = 0 p2 = len(nums) - 1 m = -math.inf while p1 < p2: if nums[p1] + nums[p2] < target: m = max(m, nums[p1] + nums[p2]) p1 += 1 else: p2 -= 1 return m nums = [8, 3, 4, 9, 2] target = 8 print(solve(nums, target))

## Input

[8, 3, 4, 9, 2], 8

## Output

7

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