# Program to find sum of the 2 power sum of all subarray sums of a given array in Python

Suppose we have a list A. We have taken all non-empty sublists of A as we know a list l with n elements has (2n - 1) non-empty sublist. Now for each sublist, he calculates sublist_sum (the sum of elements and denotes them by S1, S2, S3, ... , S(2N-1)). There is a special sum P such that P = 2S1 + 2S2 +2S3 .... + 2S(2N-1). We have to find P. If P is too large then return P mod (10^9 + 7).

So, if the input is like A = [2,2,3], then the output will be The subsets are

• {2} so 2^2 = 4
• {2} so 2^2 = 4
• {3} so 2^3 = 8
• {2,2} so 2^4 = 16
• {2,3} so 2^5 = 32
• {2,3} so 2^5 = 32
• {2,2,3} so 2^7 = 128

Sum is 4 + 4 + 8 + 16 + 32 + 32 + 128 = 224

To solve this, we will follow these steps −

• ans:= 1
• m:= 10^9+7
• for each el in A, do
• ans := ans *(1 + (2^el mod m))
• ans := ans mod m
• return (m + ans-1) mod m

## Example

Let us see the following implementation to get better understanding −

def solve(A):
ans=1
m=10**9+7

for el in A:
ans *= (1+pow(2,el,m))
ans %= m
return (m+ans-1) % m

A = [2,2,3]
print(solve(A))

## Input

[2,2,3]


## Output

224