Program to find numbers represented as linked lists in Python

PythonServer Side ProgrammingProgramming

Suppose we have two singly linked list L1 and L2, each representing a number with least significant digits first, we have to find the summed linked list.

So, if the input is like L1 = [5,6,4] L2 = [2,4,8], then the output will be [7, 0, 3, 1, ]

To solve this, we will follow these steps:

  • carry := 0

  • res := a new node with value 0

  • curr := res

  • while L1 is not empty or L2 is not empty or carry is non-zero, do

    • l0_val := value of L1 if L1 is not empty otherwise 0

    • l1_val := value of L2 if L2 is not empty otherwise 0

    • sum_ := l0_val + l1_val

    • carry := quotient of (sum_ + carry) / 10

    • add_val := remainder of (sum_ + carry) / 10

    • curr.next := a new node with value add_val

    • curr := next of curr

    • L1 := next of L1 if L1 is not empty otherwise null

    • L2 := next of L2 if L2 is not empty otherwise null

  • next of curr := null

  • return next of res

Let us see the following implementation to get better understanding:

Example

class ListNode:
   def __init__(self, data, next = None):
      self.val = data
      self.next = next

def make_list(elements):
   head = ListNode(elements[0])
   for element in elements[1:]:
      ptr = head
      while ptr.next:
         ptr = ptr.next
      ptr.next = ListNode(element)
     
   return head

def print_list(head):
   ptr = head
   print('[', end = "")
   while ptr:
      print(ptr.val, end = ", ")
      ptr = ptr.next
   print(']')

class Solution:
   def solve(self, L1, L2):
      carry = 0
      res = ListNode(0)
      curr = res

      while L1 or L2 or carry:
         l0_val = L1.val if L1 else 0
         l1_val = L2.val if L2 else 0
         sum_ = l0_val + l1_val
         carry, add_val = divmod(sum_ + carry, 10)

         curr.next = ListNode(add_val)
         curr = curr.next

         L1 = L1.next if L1 else None
         L2 = L2.next if L2 else None

      curr.next = None

return res.next

ob = Solution()
L1 = make_list([5,6,4])
L2 = make_list([2,4,8])
print_list(ob.solve(L1, L2))

Input

[5,6,4], [2,4,8]

Output

[7, 0, 3, 1, ]
raja
Published on 09-Nov-2020 10:46:03
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