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Program to find number of possible position in n-person line with few person at front and back in Python
Suppose we have three numbers n, a and b. Consider we are in a line of n people. And we are unaware about our position in the line. But we know there are at least a number of people in front of us and at most b number of people behind us. We have to find the number of possible positions possible for us.
So, if the input is like n = 10 a = 3 b = 4, then the output will be 5, because there are 10 people in the line and at least 3 are in front and at most 4 are at back. So we are at any places [0, 1, 2, 3, 4]. When we are at position 0 then 9 people are in front, 0 are behind and so on.
To solve this, we will follow these steps −
if a + b < n, then
return b + 1
if a + b >= n, then
return n - a
Example
Let us see the following implementation to get better understanding
def solve(n, a, b):
if a + b < n:
return b + 1
if a + b >= n:
return n - a
n = 10
a = 3
b = 4
print(solve(n, a, b))Input
10, 3, 4
Output
5
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