Program to find number of nodes in the sub-tree with the same label using Python

Suppose we have a rooted general tree with n nodes, whose nodes are numbered from 0 to n-1. Each node has a label with lowercase English letter. The labels are given as input in labels array, where lables[i] contains label for ith node. The tree is represented by edge list where each edge e has [u,v] represents u is parent and v is child. We have to find an array A of size n, represents number of nodes in the subtree of the ith node with same label as i

So, if the input is like

Here n = 5 and label = “ccaca”

then the output will be [3, 2, 1, 1, 1] as the root has three descendants with same label, node 1 has two descendants, and all other itself holding that label.

To solve this, we will follow these steps −

  • E := Make graph from the given edge list

  • N := a map containing each node number and its corresponding label

  • R := a list of size n and fill with 0

  • Define a function r() . This will take ni

  • C := a map to hold frequency of a key

  • for each e in E[ni], do

    • delete ni from E[e]

    • update r(e) in C

  • update N[ni] in C

  • R[ni] := C[N[ni]]

  • return C

  • From the main method call r(0)

  • return R

Let us see the following implementation to get better understanding −


 Live Demo

from collections import defaultdict, Counter
def solve(n, edges, labels):
   E = defaultdict(set)
   for f,t in edges:
   N = {i:e for i,e in enumerate(labels)}
   R = [0]*n
   def r(ni):
      C = Counter()
      for e in E[ni]:
      R[ni] = C[N[ni]]
      return C
   return R
n = 5
edges = [[0,1],[0,2],[1,3],[0,4]]
labels = "ccaca"
print(solve(n, edges, labels))


5, [[0,1],[0,2],[1,3],[0,4]], "ccaca"


[3, 2, 1, 1, 1]

Updated on: 29-May-2021


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