- Trending Categories
- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

# Program to Find Minimum Jumps Required to Reach a Value with Different Parity in Python

Suppose, we are provided with a list of numbers called nums. Here we can jump to index i + numbers[i] or to i − numbers[i] from index i if the values exist in the list. So we have to find the number of jumps required at least to reach another value with different parity keeping the order in the input unchanged. If we cannot reach another number with different parity, it is set to −1.

So, if the input is like numbers = [7, 3, 4, 5, 6, 9, 6, 7], then the output will be [−1, 1, 2, −1, −1, −1, 1, −1].

To solve this, we will follow these steps −

Define a function bfs() . This will take i

q := a new double ended queue with a pair (i, 0)

seen := a new set

while q is not empty, do

(j, d) := left most element of q and delete the leftmost item from q

add j into seen

if (nums[i] + nums[j]) mod 2 is non−zero, then

return d

for each k in [j + nums[j], j − nums[j]], do

if 0 <= k < size of nums and k is not in seen, then

insert (k, d + 1) at the right end of q

return 10^10

From the main method do the following −

ans := a new list

for i in range 0 to size of nums, do

seen := a new set

x := bfs(i)

append x in ans when x < 10^10 otherwise append −1

return ans

Let us see the following implementation to get better understanding −

## Example

from collections import deque class Solution: def solve(self, nums): def bfs(i): q = deque([(i, 0)]) seen = set() while q: j, d = q.popleft() seen.add(j) if (nums[i] + nums[j]) % 2: return d for k in [j + nums[j], j − nums[j]]: if 0 <= k < len(nums) and k not in seen: q.append((k, d + 1)) return 10 ** 10 ans = [] for i in range(len(nums)): seen = set() x = bfs(i) ans.append(x if x < 10 ** 10 else −1) return ans ob = Solution() print(ob.solve([7, 3, 4, 5, 6, 9, 6, 7]))

## Input

numbers = [7, 3, 4, 5, 6, 9, 6, 7]

## Output

[−1, 1, 2, −1, −1, −1, 1, −1]

- Related Questions & Answers
- Program to find minimum jumps to reach home in Python
- Program to find minimum number of hops required to reach end position in Python
- Program to find minimum number of buses required to reach final target in python
- Find the minimum of maximum length of a jump required to reach the last island in exactly k jumps in Python
- How to find the minimum number of jumps required to reach the end of the array using C#?
- C Program for Minimum number of jumps to reach the end
- Find minimum steps required to reach the end of a matrix in C++
- Program to find number of given operations required to reach Target in Python
- Program to find minimum required chances to form a string with K unique characters in Python
- Program to find minimum swaps required to make given anagram in python
- Program to find minimum remove required to make valid parentheses in Python
- Program to find number of minimum steps to reach last index in Python
- Program to find minimum cost to reach final index with at most k steps in python
- Program to find minimum steps to reach target position by a chess knight in Python
- Program to find minimum number of vertices to reach all nodes using Python