# Program to find minimum deletions to make string balanced in Python

PythonServer Side ProgrammingProgramming

Suppose we have a string s with only two characters 's' and 't'. We can delete any number of characters of s to make the string balanced. We can say, s is balanced when there is no pair of indices (i,j) such that i < j and s[i] = 't' and s[j]= 's'. We have to find the minimum number of deletions needed to make s balanced.

So, if the input is like s = "sststtst", then the output will be 2 because we can either, remove the characters at indices 2 and 6 ("sststtst" to "sssttt"), or remove the characters at indices 3 and 6 ("sststtst" to "sstttt").

To solve this, we will follow these steps −

• cum_b := 0

• count_a := number of character 's' in s

• ans := infinity

• for each x in s, do

• if x is same as "s", then

• count_a := count_a - 1

• ans := minimum of ans and (cum_b + count_a)

• otherwise,

• cum_b := cum_b + 1

• ans := minimum of ans and (cum_b-1 + count_a)

• return ans

## Example

Let us see the following implementation to get better understanding −

def solve(s):
cum_b = 0
count_a = s.count("s")
ans = float("inf")
for x in s:
if x == "s":
count_a-=1
ans = min(ans,cum_b + count_a)
else:
cum_b+=1
ans = min(ans,cum_b-1 + count_a)
return ans

s = "sststtst"
print(solve(s))



## Input

"sststtst"

## Output

2