Program to find minimum deletions to make string balanced in Python

Suppose we have a string s with only two characters 's' and 't'. We can delete any number of characters of s to make the string balanced. We can say, s is balanced when there is no pair of indices (i,j) such that i < j and s[i] = 't' and s[j]= 's'. We have to find the minimum number of deletions needed to make s balanced.

So, if the input is like s = "sststtst", then the output will be 2 because we can either, remove the characters at indices 2 and 6 ("sststtst" to "sssttt"), or remove the characters at indices 3 and 6 ("sststtst" to "sstttt").

To solve this, we will follow these steps −

• cum_b := 0

• count_a := number of character 's' in s

• ans := infinity

• for each x in s, do

  • if x is same as "s", then

    • count_a := count_a - 1

    • ans := minimum of ans and (cum_b + count_a)

  • otherwise,

    • cum_b := cum_b + 1

    • ans := minimum of ans and (cum_b-1 + count_a)

• return ans

Example

Let us see the following implementation to get better understanding −

def solve(s):
   cum_b = 0
   count_a = s.count("s")
   ans = float("inf")
   for x in s:
      if x == "s":
         count_a-=1
         ans = min(ans,cum_b + count_a)
      else:
         cum_b+=1
         ans = min(ans,cum_b-1 + count_a)
   return ans

s = "sststtst"
print(solve(s))

Input

"sststtst"

Output

2

Arnab Chakraborty

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Updated on: 06-Oct-2021

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