# Program to find maximum sum by flipping each row elements in Python

PythonServer Side ProgrammingProgramming

Suppose we have a 2D binary matrix. For any row or column in the given matrix we can flip all the bits. If we can perform any number of these operations, and that we treat each row as a binary number, we have to find the largest sum that can be made of these numbers.

So, if the input is like

 0 1 0 0 0 1

then the output will be 11, as if we flip both rows we get 101 and 110, then the sum is 5 + 6 = 11

To solve this, we will follow these steps −

• for each row r in matrix, do
• if r[0] is same as 0, then
• for i in range 0 to size of r, do
• r[i] := -r[i] + 1
• for j in range 1 to column size of matrix, do
• cnt := 0
• for i in range 0 to row count of matrix, do
• cnt := cnt + 1 if matrix[i, j] is 1 otherwise -1
• if cnt < 0, then
• for i in range 0 to row size of matrix, do
• matrix[i, j] := -matrix[i, j] + 1
• ans := 0
• for each row r in matrix, do
• a := 0
• for each v in r, do
• a := 2 * a + v
• ans := ans + a
• return ans

Let us see the following implementation to get better understanding −

## Example

Live Demo

class Solution:
def solve(self, matrix):
for r in matrix:
if r[0] == 0:
for i in range(len(r)):
r[i] = -r[i] + 1
for j in range(1, len(matrix[0])):
cnt = 0
for i in range(len(matrix)):
cnt += 1 if matrix[i][j] else -1
if cnt < 0:
for i in range(len(matrix)):
matrix[i][j] = -matrix[i][j] + 1
ans = 0
for r in matrix:
a = 0
for v in r:
a = 2 * a + v
ans += a
return ans
ob = Solution()
matrix = [ [0, 1, 0], [0, 0, 1] ]
print(ob.solve(matrix))

## Input

[[0, 1, 0],[0, 0, 1]]

## Output

11
Published on 19-Nov-2020 06:12:28