# Program to find length of longest palindromic substring in Python

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Suppose we have a string S. We have to find the length of longest palindromic substring in S. We are assuming that the length of the string S is 1000. So if the string is “BABAC”, then the longest palindromic substring is “BAB” and length is 3.

To solve this, we will follow these steps −

• Define one square matrix of order same as the length of string, and fill it with False

• Set the major diagonal elements as true, so DP[i, i] = True for all i from 0 to order – 1

• start := 0

• for l in range 2 to length of S + 1

• for i in range 0 to length of S – l + 1

• end := i + l

• if l = 2, then

• if S[i] = S[end - 1], then

• DP[i, end - 1] = True, max_len := l, and start := i

• otherwise

• if S[i] = S[end - 1] and DP[i + 1, end - 2], then

• DP[i, end - 1] = True, max_len := l, and start := i

• return max_len

Let us see the following implementation to get better understanding −

## Example

class Solution(object):
def solve(self, s):
dp = [[False for i in range(len(s))] for i in range(len(s))]
for i in range(len(s)):
dp[i][i] = True
max_length = 1
start = 0
for l in range(2,len(s)+1):
for i in range(len(s)-l+1):

end = i+l

if l==2:
if s[i] == s[end-1]:
dp[i][end-1]=True
max_length = l
start = i
else:
if s[i] == s[end-1] and dp[i+1][end-2]:
dp[i][end-1]=True
max_length = l
start = i
return max_length

ob = Solution()
print(ob.solve('BABAC'))

## Input

"ABBABBC"

## Output

5