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# Program to find length of longest palindromic substring after single rotation in Python

Suppose we have a string s, which we can rotate at any point exactly once. We have to find the length of the longest palindromic substring we can get by doing this operation.

So, if the input is like s = "elklev", then the output will be 7, as we can rotate between "el" and "klev" to get "levelk". So here the longest palinfromic substring length is 5.

To solve this, we will follow these steps −

s2 := concatenate s twice

max_len := 0

for x in range 0 to size of s − 1, do

for y in range 0 to size of s, do

temp := s2[from index x to x + y]

if temp is palindrome and size of temp > max_len, then

max_len := size of temp

return max_len

Let us see the following implementation to get better understanding −

## Example

class Solution: def solve(self, s): s2 = 2 * s max_len = 0 for x in range(len(s)): for y in range(len(s) + 1): temp = s2[x : x + y] if temp == temp[::−1] and len(temp) > max_len: max_len = len(temp) return max_len ob = Solution() s = "elklev" print(ob.solve(s))

## Input

"elklev"

## Output

5

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