# Program to find length of longest increasing subsequence with at least k odd values in Python

Suppose we have a list of numbers called nums and another value k, we have to find the size of the longest increasing subsequence with at least k odd elements.

So, if the input is like nums = [12, 14, 16, 5, 7, 8] k = 2, then the output will be 3, as the longest increasing subsequence with at least 2 odd values is [5, 7, 8].

To solve this, we will follow these steps −

• best := 0

• Define a function dp() . This will take i, j, odd, taken

• if odd >= k, then

• best := maximum of best and taken

• if j is same as size of nums , then

• return

• if nums[j] > nums[i], then

• dp(j, j + 1, odd +(nums[j] AND 1) , taken + 1)

• dp(i, j + 1, odd, taken)

• From the main method do the following −

• for i in range 0 to size of nums, do

• dp(i, i + 1, nums[i] AND 1, 1)

• return best

## Example

Let us see the following implementation to get better understanding −

Live Demo

class Solution:
def solve(self, nums, k):
best = 0
def dp(i, j, odd, taken):
nonlocal best
if odd >= k:
best = max(best, taken)
if j == len(nums):
return
if nums[j] > nums[i]:
dp(j, j + 1, odd + (nums[j] & 1), taken + 1)
dp(i, j + 1, odd, taken)
for i in range(len(nums)):
dp(i, i + 1, nums[i] & 1, 1)
return best
ob = Solution()
nums = [12, 14, 16, 5, 7, 8]
k = 2
print(ob.solve(nums, k))

## Input

[12, 14, 16, 5, 7, 8], 2

## Output

3

Updated on: 22-Dec-2020

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