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Suppose we have a list of sorted list of distinct integers of size n, we have to find the first positive number in range [1 to n+1] that is not present in the array.

So, if the input is like nums = [0,5,1], then the output will be 2, as 2 is the first missing number in range 1 to 5.

To solve this, we will follow these steps −

target := 1

for each i in arr, do

if i is same as target, then

target := target + 1

return target

Let us see the following implementation to get better understanding −

class Solution: def solve(self, arr): target = 1 for i in arr: if i == target: target += 1 return target ob = Solution() nums = [0,5,1] print(ob.solve(nums))

[0,5,1]

2

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