Suppose we have a list of numbers called nums and we have another number k, we have to check whether any two numbers present in the list add up to k or now. Same elements must not be used twice. And numbers can be negative or 0.
So, if the input is like nums = [45, 18, 9, 13, 12], k = 31, then the output will be True, as 18 + 13 = 31
To solve this, we will follow these steps −
Let us see the following implementation to get better understanding −
class Solution: def solve(self, nums, k): temp_set=set() for num in nums: if num in temp_set: return True temp_set.add(k-num) return False ob = Solution() nums = [45, 18, 9, 13, 12] k = 31 print(ob.solve(nums, k))
[45, 18, 9, 13, 12], 31