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Program to find all substrings whose anagrams are present in a string in Python
Suppose we have a string s with lowercase letters. We have to find all in s where there must be another substring in s at a different location that is an anagram of that taken substrings. We have to find a list of substrings in in lexicographic order.
So, if the input is like s = "abcba", then the output will be ['a', 'a', 'ab', 'abc', 'abcb', 'b', 'b', 'ba', 'bc', 'bcba', 'cb', 'cba'] for each of them we can find different anagrams present in the string itself.
To solve this, we will follow these steps −
res := a new list
L := size of s
for i in range 1 to L, do
smap := an empty dictionary, and all values are of type list
for j in range 0 to L - i, do
cs := substring of s from index j to j + i-1]
k := string after joining items of cs in sorted form
insert cs at the end of smap[k]
for each key k and value v in smap, do
if size of v >= 2, then
insert elements of v into res
return res after sorting
Example
Let us see the following implementation to get better understanding
from collections import defaultdict def solve(s): res = [] L = len(s) for i in range(1, L + 1): smap = defaultdict(list) for j in range(L - i + 1): cs = s[j : j + i] k = "".join(sorted(cs)) smap[k].append(cs) for k, v in smap.items(): if len(v) >= 2: res.extend(v) return sorted(res) s = "abcba" print(solve(s))
Input
"abcba"
Output
['a', 'a', 'ab', 'abc', 'abcb', 'b', 'b', 'ba', 'bc', 'bcba', 'cb', 'cba']
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