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Program to filter all values which are greater than x in an array
Suppose we have a list of numbers called nums. We also have another number x. We have to find all numbers from nums which are less than x by filtering. In we use python there is one filter() method that takes function as argument and filter using this function.
So, if the input is like nums = [1,5,8,3,6,9,12,77,55,36,2,5,6,12,87] x = 50, then the output will be [1, 5, 8, 3, 6, 9, 12, 36, 2, 5, 6, 12]
To solve this, we will follow these steps −
define a function f, this will take an argument a
if a < x, then return true, otherwise false
left_items := filter nums using the function f
convert filter object left_items to list and return
Example
Let us see the following implementation to get better understanding
def solve(nums, x): left_items = filter(lambda a: a < x, nums) return list(left_items) nums = [1,5,8,3,6,9,12,77,55,36,2,5,6,12,87] x = 50 print(solve(nums, x))
Input
[1,5,8,3,6,9,12,77,55,36,2,5,6,12,87], 50
Output
[1, 5, 8, 3, 6, 9, 12, 36, 2, 5, 6, 12]
Updated on: 12-Oct-2021
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