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Suppose we have a string s, we have to find the number of distinct non-empty substrings of s.

So, if the input is like s = "abaa", then the output will be 8 because, the substrings are ["a", "b", "ab", "ba", "aa", "aba", "baa", "abaa"].

To solve this, we will follow these steps −

- trie := a new map
- n := size of s
- for i in range 0 to n - 1, do
- curr := trie
- for j in range i to n - 1, do
- c := s[j]
- if c not in curr, then
- curr[c] := a new map

- curr := curr[c]
- curr["*"] := True

- q := make a queue, and insert trie
- ans := 0
- while q is non-empty, do
- ans := ans + 1
- t := left item of q, and delete this item from q
- for each c in t, do
- if c is not same as "*", then
- insert t[c] at the end of q

- if c is not same as "*", then

- return ans - 1

Let us see the following implementation to get better understanding −

from collections import deque def solve(s): trie = {} n = len(s) for i in range(n): curr = trie for j in range(i, n): c = s[j] if c not in curr: curr[c] = {} curr = curr[c] curr["*"] = True q = deque([trie]) ans = 0 while q: ans += 1 t = q.popleft() for c in t: if c != "*": q.append(t[c]) return ans - 1 s = "abaa" print(solve(s))

"abaa"

8

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