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Program to count items matching a rule using Python
Suppose we have an array nums, where each nums[i] contains three elements [type_i, color_i, name_i]. These are describing the type, color, and name of the ith item. We also have a rule represented by two other strings, ruleKey and ruleValue. Now we can say the ith item is matched the rule if one of the following is true −
ruleKey = "type" and ruleValue = type_i.
ruleKey = "color" and ruleValue = color_i.
ruleKey = "name" and ruleValue = name_i.
We have to find number of matching we can find.
So, if the input is like
| Bike | blue | ElecB |
| Car | silver | Sumo |
| Bike | blue | TVS |
And ruleKey = "color", ruleValue = "blue", then the output will be 2 as there are two match [["Bike","blue","ElecB"] and ["Bike","blue","TVS"]].
To solve this, we will follow these steps −
count := 0
if ruleKey is same as "type", then
for i in range 0 to size of items, do
if items[i, 0] is same as ruleValue, then
count := count + 1
if ruleKey is same as "color", then
for i in range 0 to size of items, do
if items[i, 1] is same as ruleValue, then
count := count + 1
if ruleKey is same as "name", then
for i in range 0 to size of items, do
if items[i, 2] is same as ruleValue, then
count := count + 1
return count
Let us see the following implementation to get better understanding −
Example
def solve(items, ruleKey, ruleValue): count = 0 if ruleKey == "type": for i in range(len(items)): if items[i][0] == ruleValue: count += 1 if ruleKey == "color": for i in range(len(items)): if items[i][1] == ruleValue: count += 1 if ruleKey == "name": for i in range(len(items)): if items[i][2] == ruleValue: count += 1 return count items = [["Bike","blue","ElecB"],["Car","silver","Sumo"],["Bike","blue","TVS"]] ruleKey = "color" ruleValue = "blue" print(solve(items, ruleKey, ruleValue))
Input
[["Bike","blue","ElecB"],["Car","silver","Sumo"],["Bike","blue","TVS"]],"color", "blue"
Output
2
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