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Program to convert ASCII to HEX in 8085 Microprocessor
Here we will see one 8085 Microprocessor program. This program will convert ASCII to HEX values.
Problem Statement −
Write an 8085 Assembly language program to convert ASCII to Hexadecimal character values.
Discussion −
We know that the ASCII of number 00H is 30H (48D), and ASCII of 09H is 39H (57D). So all other numbers are in the range 30H to 39H. The ASCII value of 0AH is 41H (65D) and ASCII of 0FH is 46H (70D), so all other alphabets (B, C, D, E, F) are in the range 41H to 46H.
Here the logic is simple. We are checking whether the ASCII value is less than 58H (ASCII of 9 + 1) When the number is less 58, then it is numeric value. So we simply subtract 30H from the ASCII value, and when it is greater than 58H, then it is alphabetical value. So for that we are subtracting 37H.
Input
first input
| Address | Data |
|---|---|
| … | … |
| 8000 | 41 |
| … | … |
second input
| Address | Data |
|---|---|
| … | … |
| 8000 | 35 |
| … | … |
third input
| Address | Data |
|---|---|
| … | … |
| 8000 | 46 |
| … | … |
Flow Diagram
Program
| Address | HEX Codes | Labels | Mnemonics | Comments |
|---|---|---|---|---|
| F000 | 21, 00, 80 | LXI H, 8000H | Load address of the number | |
| F003 | 7E | MOV A,M | Load ASCII data to Acc from memory | |
| F004 | FE, 58 | CPI 58H | Compare with ASCII(9) + 1 | |
| F006 | D2, 0E, F0 | JNC NUM | The input is numeric | |
| F009 | D6, 37 | SUI 37H | Subtract offset to get Alphabetic character | |
| F00B | C3, 10, F0 | JMP STORE | Store the result | |
| F00E | D6, 30 | NUM | SUI 30H | Subtract 30 to get numeric value |
| F010 | 23 | STORE | INX H | Point to next location |
| F011 | 77 | MOV M,A | Store Acc content to memory | |
| F012 | 76 | HLT | Terminate the program |
Output
first output
| Address | Data |
|---|---|
| … | … |
| 8001 | 0A |
| … | … |
second output
| Address | Data |
|---|---|
| … | … |
| 8001 | 05 |
| … | … |
third output
| Address | Data |
|---|---|
| … | … |
| 8001 | 0F |
| … | … |
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