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Program to check whether final string can be formed using other two strings or not in Python
Suppose we have two strings s, t, and another string r we have to check whether there is any way to get r by merging characters in order from s and t.
So, if the input is like s = "xyz" t = "mno" r = "xymnoz", then the output will be True, as xymnoz can be formed by interleaving xyz and mno.
To solve this, we will follow these steps −
Define a function solve() . This will take s, t, r
if s, t and r are empty, then
return True
if r is empty, then
return False
if s is empty, then
return true when t is same as r, otherwise false
if not t is non−zero, then
return s is same as r
if s[0] is same as r[0], then
if solve(s[from index 1 to end], t, r[from index 1 to end]) is true, then
return True
if t[0] is same as r[0], then
if solve(s, t[from index 1 to end], r[from index 1 to end]) is true, then
return True
return False
Let us see the following implementation to get better understanding −
Example
class Solution: def solve(self, s, t, r): if not s and not t and not r: return True if not r: return False if not s: return t == r if not t: return s == r if s[0] == r[0]: if self.solve(s[1:], t, r[1:]): return True if t[0] == r[0]: if self.solve(s, t[1:], r[1:]): return True return False ob = Solution() s = "xyz" t = "mno" r = "xymnoz" print(ob.solve(s, t, r))
Input
"xyz", "mno", "xymnoz"
Output
True
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