Suppose we have a list of numbers called nums, we have to check whether there is an element whose frequency is same as its value.
So, if the input is like nums = [2,5,7,5,3,5,3,5,9,9,5], then the output will be True, because 5 appears 5 times.
To solve this, we will follow these steps −
nums_c := a list containing frequencies of each elements present in nums
for each value i and frequency j in nums_c, do
if i is same as j, then
Let us see the following implementation to get better understanding
from collections import Counter def solve(nums): nums_c = Counter(nums) for i, j in nums_c.items(): if i == j: return True return False nums = [2,5,7,5,3,5,3,5,9,9,5] print(solve(nums))