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# Program to add one to a number that is shown as a digit list in Python

Suppose we have an array called nums, containing decimal digits of a number. For example, [2, 5, 6] is for 256. We have to add 1 with this number and return the list in same format as before.

So, if the input is like nums = [2, 6, 9], then the output will be [2, 7, 0].

To solve this, we will follow these steps −

i := size of nums - 1

while i >= 0, do

if nums[i] + 1 <= 9, then

nums[i] := nums[i] + 1

come out from loop

otherwise,

nums[i] := 0

i := i - 1

if i < 0, then

insert 1 into nums at position 0

return nums

## Example

Let us see the following implementation to get better understanding

def solve(nums): i = len(nums) - 1 while i >= 0: if nums[i] + 1 <= 9: nums[i] = nums[i] + 1 break else: nums[i] = 0 i -= 1 if i < 0: nums.insert(0, 1) return nums nums = [2, 6, 9] print(solve(nums))

## Input

[2, 6, 9]

## Output

[2, 7, 0]

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