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Program for volume of Pyramid in C++
Given with sides depending upon the type of base of pyramid the task is to calculate the volume of pyramid.
Pyramid is a 3-D figure whose outer surfaces are triangular meeting at the common point forming the sharp edge of pyramid. Volume of pyramid depends upon the type of base it will have.
There are different types of base a pyramid can be made up of, like −
Triangular −It means pyramid will have triangular base, than the volume of pyramid will be
Formula - : (1/6) * a * b * h
Square −It means pyramid will have square base, than the volume of pyramid will be
Formula - : (1/3) * (b^2) * h
Pentagonal −It means pyramid will have pentagonal base, than the volume of pyramid will be
formula - : (5/6) * a * b * h
Hexagonal −It means pyramid will have hexagonal base, than the volume of pyramid will be
formula - : a * b * h
Example
Input-: a=4 b=2 h=10 Output-: Volume of pyramid with triangular base is 13.328 Volume of pyramid with square base is 13.2 Volume of pyramid with pentagonal base is 66.4 Volume of pyramid with hexagonal base is 80
Given below is the pyramid with square base
Algorithm
Start Step 1 -> Declare function to find the volume of triangular pyramid float volumeTriangular(int a, int b, int h) Declare variable float volume = (0.1666) * a * b * h return volume step 2 -> Declare Function to find the volume of square pyramid float volumeSquare(int b, int h) declare and set float volume = (0.33) * b * b * h return volume Step 3 -> Declare Function to find the volume of pentagonal pyramid float volumePentagonal(int a, int b, int h) declare and set float volume = (0.83) * a * b * h return volume Step 4 -> Declare Function to find the volume of hexagonal pyramid float volumeHexagonal(int a, int b, int h) declare and set float volume = a * b * h return volume Step 5 -> In main() Declare variables as int b = 2, h = 10, a = 4 Call volumeTriangular(a, b, h) Call volumeSquare(b,h) Call volumePentagonal(a, b, h) Call volumeHexagonal(a, b, h) Stop
Example
#include <bits/stdc++.h>
using namespace std;
// Function to find the volume of triangular pyramid
float volumeTriangular(int a, int b, int h){
float volume = (0.1666) * a * b * h;
return volume;
}
// Function to find the volume of square pyramid
float volumeSquare(int b, int h){
float volume = (0.33) * b * b * h;
return volume;
}
// Function to find the volume of pentagonal pyramid
float volumePentagonal(int a, int b, int h){
float volume = (0.83) * a * b * h;
return volume;
}
// Function to find the volume of hexagonal pyramid
float volumeHexagonal(int a, int b, int h){
float volume = a * b * h;
return volume;
}
int main(){
int b = 2, h = 10, a = 4;
cout << "Volume of pyramid with triangular base is "<<volumeTriangular(a, b, h)<<endl;
cout << "Volume of pyramid with square base is "<<volumeSquare(b, h)<< endl;
cout << "Volume of pyramid with pentagonal base is "<<volumePentagonal(a, b, h)<< endl;
cout << "Volume of pyramid with hexagonal base is "<<volumeHexagonal(a, b, h);
return 0;
}Output
Volume of pyramid with triangular base is 13.328 Volume of pyramid with square base is 13.2 Volume of pyramid with pentagonal base is 66.4 Volume of pyramid with hexagonal base is 80
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