Program for decimal to hexadecimal conversion in C++

Given with a decimal number as an input, the task is to convert the given decimal number into a hexadecimal number.

Hexadecimal number in computers is represented with base 16 and decimal number is represented with base 10 and represented with values 0 - 9 whereas hexadecimal number have digits starting from 0 – 15 in which 10 is represented as A, 11 as B, 12 as C, 13 as D, 14 as E and 15 as F.

To convert a decimal number into a hexadecimal number follow the given steps −

Firstly divide the given number with the base value of conversion number e.g. dividing 6789 by 16 because we need to convert 6789 into a hexadecimal numbers which have base 16 and then obtain a quotient and store it. If the remainder is between 0-9 store them as it is and if the remainder lies between 10-15 convert them in their character form as A - F
Divide the obtained quotient with the base value of hexadecimal number which is 16 and keep storing the bits.
Keep doing right shift to the stored bits
Repeat the step until the remainder left indivisible

Given below is the pictorial representation of converting a decimal number into a hexadecimal number.

Example

Input-: 6789
   Divide the 6789 with base 16 : 6789 / 16 = 5 (remainder) 424(quotient)
   Divide quotient with base: 424 / 16 = 8(remainder) 26(quotient)
   Divide quotient with base: 26 / 16 = 10(remainder) 1(quotient)
   Now reverse the remainder obtained for final hexadecimal value.
Output-: 1A85

Algorithm

Start
Step 1-> Declare function to convert decimal to hexadecimal
   void convert(int num)
      declare char arr[100]
      set int i = 0
      Loop While(num!=0)
         Set int temp = 0
         Set temp = num % 16
         IF temp < 10
            Set arr[i] = temp + 48
            Increment i++
         End
         Else
            Set arr[i] = temp + 55
            Increment i++
         End
         Set num = num/16
      End
      Loop For int j=i-1 j>=0 j—
         Print arr[j]
Step 2-> In main()
   Set int num = 6789
   Call convert(num)
Stop

Example

Live Demo

#include<iostream>
using namespace std;
//convert decimal to hexadecimal
void convert(int num) {
   char arr[100];
   int i = 0;
   while(num!=0) {
      int temp = 0;
      temp = num % 16;
      if(temp < 10) {
         arr[i] = temp + 48;
         i++;
      } else {
         arr[i] = temp + 55;
         i++;
      }
      num = num/16;
   }
   for(int j=i-1; j>=0; j--)
   cout << arr[j];
}
int main() {
   int num = 6789;
   cout<<num<< " converted to hexadeciaml: ";
   convert(num);
   return 0;
}

Output

IF WE RUN THE ABOVE CODE IT WILL GENERATE FOLLOWING OUTPUT

6789 converted to hexadeciaml: 1A85

Sunidhi Bansal

Published on 18-Oct-2019 08:17:51

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