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Program for decimal to hexadecimal conversion in C++
Given with a decimal number as an input, the task is to convert the given decimal number into a hexadecimal number.
Hexadecimal number in computers is represented with base 16 and decimal number is represented with base 10 and represented with values 0 - 9 whereas hexadecimal number have digits starting from 0 – 15 in which 10 is represented as A, 11 as B, 12 as C, 13 as D, 14 as E and 15 as F.
To convert a decimal number into a hexadecimal number follow the given steps −
- Firstly divide the given number with the base value of conversion number e.g. dividing 6789 by 16 because we need to convert 6789 into a hexadecimal numbers which have base 16 and then obtain a quotient and store it. If the remainder is between 0-9 store them as it is and if the remainder lies between 10-15 convert them in their character form as A - F
- Divide the obtained quotient with the base value of hexadecimal number which is 16 and keep storing the bits.
- Keep doing right shift to the stored bits
- Repeat the step until the remainder left indivisible
Given below is the pictorial representation of converting a decimal number into a hexadecimal number.
Example
Input-: 6789 Divide the 6789 with base 16 : 6789 / 16 = 5 (remainder) 424(quotient) Divide quotient with base: 424 / 16 = 8(remainder) 26(quotient) Divide quotient with base: 26 / 16 = 10(remainder) 1(quotient) Now reverse the remainder obtained for final hexadecimal value. Output-: 1A85
Algorithm
Start Step 1-> Declare function to convert decimal to hexadecimal void convert(int num) declare char arr[100] set int i = 0 Loop While(num!=0) Set int temp = 0 Set temp = num % 16 IF temp < 10 Set arr[i] = temp + 48 Increment i++ End Else Set arr[i] = temp + 55 Increment i++ End Set num = num/16 End Loop For int j=i-1 j>=0 j— Print arr[j] Step 2-> In main() Set int num = 6789 Call convert(num) Stop
Example
#include<iostream>
using namespace std;
//convert decimal to hexadecimal
void convert(int num) {
char arr[100];
int i = 0;
while(num!=0) {
int temp = 0;
temp = num % 16;
if(temp < 10) {
arr[i] = temp + 48;
i++;
} else {
arr[i] = temp + 55;
i++;
}
num = num/16;
}
for(int j=i-1; j>=0; j--)
cout << arr[j];
}
int main() {
int num = 6789;
cout<<num<< " converted to hexadeciaml: ";
convert(num);
return 0;
}Output
IF WE RUN THE ABOVE CODE IT WILL GENERATE FOLLOWING OUTPUT
6789 converted to hexadeciaml: 1A85
Updated on: 18-Oct-2019
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