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C++ program for hexadecimal to decimal
Given with a hexadecimal number as an input, the task is to convert the given hexadecimal number into a decimal number.
Hexadecimal number in computers is represented with base 16 and decimal number is represented with base 10 and represented with values 0 - 9 whereas hexadecimal number have digits starting from 0 – 15 in which 10 is represented as A, 11 as B, 12 as C, 13 as D, 14 as E and 15 as F.
To convert a hexadecimal number into a decimal number follow these steps −
- We will extract digits starting from right to left through a remainder and then multiply it with the power starting from 0 and will be increased by 1 till the (number of digits) – 1
- Since we need to do conversions from hexdecimal to binary the base of power will be 16 as octal have base 16.
- Multiply the digits of given inputs with base and power and store the results
- Add all the multiplied values to obtain the final result which will be a decimal number.
Given below is the pictorial representation of converting a hexadecimal number into a decimal number.
Example
Input-: ACD A(10) will be converted to a decimal number by -: 10 X 16^2 = 2560 C(12) will be converted to a decimal number by -: 12 X 16^1 = 192 D(13) will be converted to a decimal number by -: 13 X 16^0 = 13 Output-: total = 13 + 192 + 2560 = 2765
Algorithm
Start Step 1-> declare function to convert hexadecimal to decimal int convert(char num[]) Set int len = strlen(num) Set int base = 1 Set int temp = 0 Loop For int i=len-1 and i>=0 and i— IF (num[i]>='0' && num[i]<='9') Set temp += (num[i] - 48)*base Set base = base * 16 End Else If (num[i]>='A' && num[i]<='F') Set temp += (num[i] - 55)*base Set base = base*16 End return temp step 2-> In main() declare char num[] = "3F456A" Call convert(num) Stop
Example
#include<iostream>
#include<string.h>
using namespace std;
//convert hexadecimal to decimal
int convert(char num[]) {
int len = strlen(num);
int base = 1;
int temp = 0;
for (int i=len-1; i>=0; i--) {
if (num[i]>='0' && num[i]<='9') {
temp += (num[i] - 48)*base;
base = base * 16;
}
else if (num[i]>='A' && num[i]<='F') {
temp += (num[i] - 55)*base;
base = base*16;
}
}
return temp;
}
int main() {
char num[] = "3F456A";
cout<<num<<" after converting to deciaml becomes : "<<convert(num)<<endl;
return 0;
}Output
IF WE RUN THE ABOVE CODE IT WILL GENERATE FOLLOWING OUTPUT
3F456A after converting to deciaml becomes : 4146538
Updated on: 18-Oct-2019
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