Program for adding 4 hex digits of a 16-bit number in 8085 Microprocessor

MicroprocessorMicrocontroller8085

We write an 8085 assembly language program for the addition of 4 hex digits of a 16-bit number whose input is given from the keyboard and the result is displayed in the data field.

FILE NAME ADDHEX.ASM
ORG C000H
CURDT: EQU FFF9H
UPDDT: EQU 06D3H
GTHEX: EQU 052FH
HXDSP: EQU 05A1H
OBUFF: EQU FFFAH
MVI A, 0EH
SIM
EI ; Unmask RST5.5 and enable interrupts
MVI B, 00
CALL GTHEX ; Input a 4 digit number and display in address field
CALL HXDSP ; Store the 4 hex digits in 4 locations starting from OBUFF
LXI H, OBUUF
MOV A, M
MVI C, 03
AGAIN: INX H
ADD M
DCR C
JNZ AGAIN ; When we are out of this loop, A will have the sum.
STA CURDT
CALL UPDDT ; Display sum in DATA field.
HLT

In the above program we use the HXDSP monitor routine for the first time.

HXDSP monitor routine: This routine is used for the conversion of the value in DE register pair and which stores in the location of 4 bytes starting from the output buffer. The Least Significant unpacked hex byte gets stored in the Output Buffer. On the ALS kit the OBUFF is of location FFFAH, and HXDSP routine which STARTS AT 05A1H. Hence if (DE) + 3456, we will have

raja
Published on 27-Mar-2019 13:46:40
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