Private Methods in Java 9 Interfaces

Following is an example displaying how to use private methods in Java 9 Interfaces −

Example

interface my_int{
   public abstract void multiply_vals(int a, int b);
   public default void add_vals(int a, int b){
      sub_vals(a, b);
      System.out.print("Default method result ");
      System.out.println(a + b);
   }
   private void sub_vals(int a, int b){
      System.out.print("Private method result ");
      System.out.println(a - b);
   }
   private static void div(int a, int b){
      System.out.print(" Private static method result ");
      System.out.println(a / b);
   }
}
public class my_new_int implements my_int{
   @Override
   public void multiply_vals(int a, int b){
      System.out.print("Abstract method result ");
      System.out.println(a * b);
   }
   public static void main(String[] args){
      my_int in = new my_new_int();
      in.multiply_vals(11, 34);
      in.add_vals(78, 0);
   }
}

Output

Abstract method result 374
Private method result 78
Default method result 78

An interface named ‘my_int’ is defined, that has an abstract function, without a body. Another default function is defined, that basically adds two numbers. Another function named ‘sub_vals’ is defined, which subtracts the two numbers.

Another static function named div is defined that divides the two values. A class named ‘my_new_int’ implements the previously defined interface. It overrides the function that multiplies values and redefines it. In the main function, an instance of the interface is created, and the ‘multiply_vals’ function is called by passing specific values. Similarly, the ‘add_vals’ function is also called by passing specific values. The respective output is displayed on the console.

AmitDiwan

Published on 14-Jul-2020 07:05:58