You are applying force on the pan of single pan weighing balance and the pointer points to $100\ g$. What is the force in newtons applied by you?


Here, mass of thee pen $m=100\ g=\frac{100}{1000}\ kg.=\frac{1}{10}\ kg.$

Therefore, applied force to hold the pen$=$weight of the pan

$=mg$      [$g\rightarrow$ gravity constant, on earth $g=9.8\ m/s^2$]

$=\frac{1}{10}\ kg.\times 9.8$

$=0.98\ N$

Updated on: 10-Oct-2022

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