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You are applying force on the pan of single pan weighing balance and the pointer points to $100\ g$. What is the force in newtons applied by you?
Here, mass of thee pen $m=100\ g=\frac{100}{1000}\ kg.=\frac{1}{10}\ kg.$
Therefore, applied force to hold the pen$=$weight of the pan
$=mg$ [$g\rightarrow$ gravity constant, on earth $g=9.8\ m/s^2$]
$=\frac{1}{10}\ kg.\times 9.8$
$=0.98\ N$
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