Write two solutions of the form $x = 0, y = a$ and $x = b, y = 0$ for each of the following equations.$-4x + 3y = 12$

Given:

$-4x + 3y = 12$

To do:

We have to write two solutions of the form $x = 0, y = a$ and $x = b, y = 0$ for the given equation.

Solution:

$-4x + 3y = 12$

Let $x=0$, this implies,

$-4(0)+3y=12$

$\Rightarrow 0+3y=12$

$\Rightarrow y=\frac{12}{3}=4$

Therefore, $x=0, y=4$ is a solution of the equation $-4x + 3y = 12$.

Let $y=0$, this implies,

$-4x+3(0)=12$

$\Rightarrow -4x=12$

$\Rightarrow x=\frac{12}{-4}=-3$

Therefore, $x=-3, y=0$ is a solution of the equation $-4x + 3y = 12$.  

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Updated on: 10-Oct-2022

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