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What is the smallest natural number which is divisible by 25 and 55?
Given:
Given numbers are 25 and 55.
To find:
Here, we have to find the smallest natural number which is divisible by both 25 and 55.
Solution:
The smallest number which is divisible by any two numbers is their LCM.
Now,
Writing the numbers as a product of their prime factors:
Prime factorisation of 25:
- $25=5\times5=5^2$
Prime factorisation of 55:
- $55=5\times11=5^1\times11^1$
Multiplying the highest power of each prime number:
- $5^2\times11^1=25\times11=275$
LCM(25, 55) $=$ 275
So, the smallest number which is divisible by both 25 and 55 is 275.
Updated on: 10-Oct-2022
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