What is the additive inverse of $\frac{7}{19}$?

Given:

Given number is $\frac{7}{19}$.

To do:

We have to find the additive inverse of the given number.

Solution :   

Additive inverse of a number 'a' is '$-a$'.

$\displaystyle a\ +\ ( -a) \ =\ 0$       

Let the additive inverse of $\frac{7}{19}$ be x.

$\frac{7}{19} + x = 0$ $x =-\frac{7}{19}$.

So, Additive inverse of $\frac{7}{19}$ is $-\frac{7}{19}$.                                      

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Updated on: 10-Oct-2022

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